Competition:Analysis of Data:Sample Experiment
Analysis of Data and Interpretation of Results from Sample Experiment
In this section the data generated from the sample competition experiment will be
analyzed. This section assumes that you know how to plot these graphs
and
determine IC50 values
as described on the previous two pages. You
will be lead through the following steps:
- In the first step you will be asked to convert the concentration of prazosin added
into log units.
- The data will be plotted three ways: Bound (cpm) versus - Log of Prazosin, % of
Control versus the - Log of Prazosin, and % of Specific Bound versus the - Log of
Prazosin. These plots were explained in the previous section.
You will be
asked to calculate the values needed to plot the data.
- You will be asked to estimate the IC50 values from each plot. You will be
given the results of the nonlinear regression analysis of the data.
You will be asked to calculate the Ki value from the IC50
value. To do this you will be asked to calculate the concentration of [3H]RX821002
actually present in the assay tubes.
Click here to review the
purpose of sample experiment.
Analysis of Data as Average Bound (cpm) versus the - Log of Prazosin
- The following table lists the concentrations of prazosin that were used in the sample
experiment. Please convert the prazosin concentration Molar units (Use E to represent the
exponential value of 10. For example 10-9 = E-9). Next covert the molar units
to log (M) units and place the answers in the following table.
The Bound (cpm) values obtained from the 12 sets of duplicate tubes are given in the
table below. Matthew has entered the results of your calculations of Log of Prazosin in
the first column. Note the 0 concentration of prazosin has been converted to Log
-12. This value is > 10 fold lower than than the lowest concentration of prazosin used.
It simplifies plotting the data on the graph. Please calculate the Average
Bound (cpm) to the nearest whole number and enter the values in the table.
The plot of Bound (cpm) versus - Log of Prazosin looks like this:
Note the following factors on this graph
- The curve shown on the graph was generated using a nonlinear regression analysis for
one-site competition using the Prism computer program.
- The first point on the graph is the control value that was obtained by adding the
diluent for prazosin. It is difficult to plot the results as 0 concentration as this
requires a break in X-axis. One way around this is to express the control value as a
concentration of the unlabeled drug that is 10 to 100 fold lower than the lowest
concentration of unlabeled ligand. In this instance a prazosin concentration of 10-11
M was chosen to represent the control value.
- The amount of radioligand bound in the presence of 30 然 norepinephrine (NE) is shown.
Remember that norepinephrine was used as a marker to tell us where the bottom of the curve
should be. The since amount of [3H]RX821002 bound at the lowest concentration
of prazosin is similar to that obtained with norepinephrine, it indicates that prazosin is
blocking all of the sites that norepinephrine is blocking.
- The top of the curve does not go through the zero control value and is not well defined.
The lower end of the curve is well defined. A better designed experiment would be to use
prazosin concentrations between 0.1 nM and 3 然.
Estimate the IC50 for prazosin in the graph above.

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The purpose of the experiment is to determine the Ki for
prazosin binding to alpha-2B adrenergic receptor transfected into CHO cells. The Ki
for prazosin is determined by measuring the binding of [3H]RX821002 in the
presence of increasing concentrations of prazosin. The assay buffer used is 25 mM sodium
phosphate, pH 7.4. Saturation experiments using the alpha-2B adrenergic receptor in these
cells with this buffer gave a Kd of 890 pM for [3H]RX821002 and a Bmax
of 2.2 pmol/mg protein. The specific activity for [3H]RX821002 is 59 Ci/mmol
and is provided as 1 湣i/ml. Nonspecific binding is determined using 0.1 mM
norepinephrine (NE). Duplicate tubes are set up for each condition.
The estimated IC50 is 10-8 M or 10 nM
Explanation:
The IC50 is the concentration of prazosin required to inhibit
specific binding of [3H]RX821002 by 50%. Fifty percent of specific binding is
halfway between the middle and bottom of the curve. Note: Specific binding is not
between the middle of the curve and the bottom of the graph.

The IC50 value, determined using nonlinear regression of the
equation for a sigmoid plot, gave a Log IC50 of -8.042 which would be 9.076 nM.
Nonlinear regression analysis of competition curves is done in the same manner as for
saturation curves except that a different equation for the line is used.

Both values are correct, please continue.
The Molar value is correct, but the Log(M) value is incorrect. Please try again!
The Log(M) value is incorrect, but the Molar value is correct. Please try again!
Both values are incorrect. please try the calculation again.
Your answer is correct please continue..
Your answer is incorrect, please try again! Try rounding to nearest whole number