Competition:Analysis of Data:Sample Experiment:% of Control

Analysis of Data as Percent of Control Versus - Log Prazosin

On this page you will convert the data to % of Control and estimate the IC50 value from a plot of % of Control versus -Log Prazosin.

cartoon1.gif (688 bytes)

Matthew has placed you calculations from the previous table in the table below

You now need to calculate the % of Control.  

Calculate the % of control now and enter the results in the last column.  Use the value obtained in the absence of prazosin (Log -12) as the control value.

Prazosin
Log
(M)
Bound
(cpm)
%
of Control

- 12.00

1395

- 9.52

1292

-9.00

1256

-8.52

958

-8.00

730

-7.52

417

-7.00

198

-6.52

126

-6.00

116

-5.52

82

-5.00

81

The plot of % of Control versus Log of the Prazosin Concentration looks like this:

Estimate the IC50 from this graph.
What is the advantage of using % of Control rather than Bound (cpm) on the Y-axis?

Continue to analyze the data as percent of Specific Bound vs. - Log Prazosin

The estimated IC50 is 10-8 M or 10 nM

Nonlinear regression analysis of % of Control versus the Log Prazosin using the equation for a competition curve gave the following results

Log of IC50 = -8.042

IC50 = 9.075 x 10-9 M or 9.075 nM

Results tend to vary from one day to the next for the amount bound in the control tubes and bound in the presence of a high concentration of unlabeled ligand. This makes it difficult to plot different sets of data on the same graph. You can compensate for this to some extent by using % of Control. % of Control does not compensate for variations in the amount of nonspecific bound from one experiment to another.

Your answer is correct, please continue..

Hint: Express as a percent
(cpm Bound/1395) * 100